Marilla's teacher gave her four fractions to locate on a number line: #1/3, 7/10, 2/3, and 5/8#. How would you arrange these from the least to the greatest? Algebra

May 2, 2018 · see explanation. Let L_1 be the perpendicular bisector of the line AB, => L_1 passes through AB's midpoint at 90^@, let M be the midpoint of AB, => M= ( (4+10)/2, (6 ...

Please see below. An equation of the form y=a(x-h)^2+k has x-h=0 as axis of symmetry and (h,k) as vertex. Such an equation is a vertical parabola and if a is positive, it open up and if a is …

Jul 22, 2017 #int_2^6sqrt (x)logxdx=# #2/ (3ln10) ( (ln6-2/3)sqrt (216)+ (2/3-ln2)sqrt8)#

n = 22/15 Your starting equation looks like this (a^4)^ (1/5) * (a^2)^ (1/3) = a^n You will use two properties of exponents to find the value of n the power of a power property power of a product …

10/3 pounds 'of' implies multiplication. 2/3 of 5 = 2/3 * 5 2/3 * 5 = 2/3 * 5/1 = (2*5)/(3*1) = 10/3 10/3 pounds, or 3 1/3 pounds, of the 5 pounds of chocolate bought was white chocolate.

Kiera = 4560 pounds Larry = 2280 pounds Gita = 1520 pounds The “problem statement” is really just long, not complex. The value of mathematics is in solving real-world problems. Those …

The interval of decreasing is x in ]-oo,-2 [ The interval of increasing is x in ]-2,+oo [ We need (x^n)=nx^ (n-1) We calculate the first derivative y= (x+2)^ (2/3) dy ...

You state #m+2/3+1/4m-1# and you use the word 'solve'. This implies that you wish to determine the value of #m#.

x=-1+-sqrt6/3 >"to "color (blue)"complete the square" • " the coefficient of the "x^2" term must be 1" rArr3 (x^2+2x+1/3)=0 • " add/subtract " (1/2"coefficient of the x-term")^2" to" x^2+2x rArr3 …